People on Mars count their numbers with base 13:

• Zero on Earth is called “tret” on Mars.
• The numbers 1 to 12 on Earth is called “jan, feb, mar, apr, may, jun, jly, aug, sep, oct, nov, dec” on Mars, respectively.
• For the next higher digit, Mars people name the 12 numbers as “tam, hel, maa, huh, tou, kes, hei, elo, syy, lok, mer, jou”, respectively.

For examples, the number 29 on Earth is called “hel mar” on Mars; and “elo nov” on Mars corresponds to 115 on Earth. In order to help communication between people from these two planets, you are supposed to write a program for mutual translation between Earth and Mars number systems.

Input Specification:

Each input file contains one test case. For each case, the first line contains a positive integer N (<100). Then N lines follow, each contains a number in [0, 169), given either in the form of an Earth number, or that of Mars.

Output Specification:

For each number, print in a line the corresponding number in the other language.

Sample Input:

4
29
5
elo nov
tam

Sample Output:

hel mar
may
115
13

思路

直接针对给出的输入进行模拟会相对复杂，考虑到数据范围最多不超过168，因此不妨将 [0, 168] 的所有数都预处理出来（即打表），然后查询一个输出一个即可。

注意点

• 由于个位或十位为 0 时，不应该将其输出为 “tret”，所以在大表时，应该将个位或十位为 0 的数与其他数分开考虑。

#include <iostream>
#include <string>
#include <map>
using namespace std;

int n;
string num[4];
string unitDigit[13] = {"tret", "jan", "feb", "mar", "apr", "may", "jun", "jly", "aug", "sep", "oct", "nov", "dec"};
string tenDigit[13] = {"tret", "tam", "hel", "maa", "huh", "tou", "kes", "hei", "elo", "syy", "lok", "mer", "jou"};
map<string, int> marsToNum;
string numToMars[170];

void init() {
    for (int i = 0; i < 13; i++) {
        numToMars[i] = unitDigit[i];
        marsToNum[unitDigit[i]] = i;
        numToMars[i * 13] = tenDigit[i];
        marsToNum[tenDigit[i]] = i * 13;
    }
    for (int i = 1; i < 13; i++) {
        for (int j = 1; j < 13; j++) {
            string mars = tenDigit[i] + " " + unitDigit[j];
            numToMars[i * 13 + j] = mars;
            marsToNum[mars] = i * 13 + j;
        }
    }
}

int main() {
    scanf("%d", &n);
    getchar();
    string str;
    init();
    for (int i = 0; i < n; i++) {
        getline(cin, str);
        if (str[0] >= '0' && str[0] <= '9') {
            printf("%s\n", numToMars[stoi(str)].c_str());
        } else {
            printf("%d\n", marsToNum[str]);
        }
    }
    return 0;
}